0=x^2-3x+38

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Solution for 0=x^2-3x+38 equation: 



0=x^2-3x+38

We move all terms to the left:

0-(x^2-3x+38)=0

We add all the numbers together, and all the variables

-(x^2-3x+38)=0

We get rid of parentheses

-x^2+3x-38=0

We add all the numbers together, and all the variables

-1x^2+3x-38=0

a = -1; b = 3; c = -38;
Δ = b2-4ac
Δ = 32-4·(-1)·(-38)
Δ = -143
Delta is less than zero, so there is no solution for the equation

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